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W3spoint99
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Asked: January 17, 2025In: Angular

What is the difference between Promises and Observables?

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What is the difference between Promise and Observable in Angular? An example on each would be helpful in understanding both the cases. In what scenario can we use each case?

angularangular observableangular promisepromiserxjs
  1. Saralyn
    Saralyn Teacher
    Added an answer on January 17, 2025 at 2:03 pm

    Both Promises and Observables provide us with abstractions that help us deal with the asynchronous nature of our applications. The difference between them was pointed out clearly by Günter and @Relu. Since a code snippet is worth a thousand words, let’s go through the below example to understand theRead more

    Both Promises and Observables provide us with abstractions that help us deal with the asynchronous nature of our applications. The difference between them was pointed out clearly by Günter and @Relu.

    Since a code snippet is worth a thousand words, let’s go through the below example to understand them easier.

    Thanks @Christoph Burgdorf for the awesome article


    Angular uses Rx.js Observables instead of promises for dealing with HTTP.

    Suppose that you are building a search function that should instantly show you results as you type. It sounds familiar, but there are a lot of challenges that come with that task.

    • We don’t want to hit the server endpoint every time user presses a key. It should flood them with a storm of HTTP requests. Basically, we only want to hit it once the user has stopped typing instead of with every keystroke.
    • Don’t hit the search endpoint with the same query parameters for subsequent requests.
    • Deal with out-of-order responses. When we have multiple requests in-flight at the same time we must account for cases where they come back in unexpected order. Imagine we first type computer, stop, a request goes out, we type car, stop, a request goes out. Now we have two requests in-flight. Unfortunately, the request that carries the results for computer comes back after the request that carries the results for car.

    The demo will simply consist of two files: app.ts and wikipedia-service.ts. In a real world scenario, we would most likely split things further up, though.


    Below is a Promise-based implementation that doesn’t handle any of the described edge cases.

    wikipedia-service.ts

    import { Injectable } from '@angular/core';
    import { URLSearchParams, Jsonp } from '@angular/http';
    
    @Injectable()
    export class WikipediaService {
      constructor(private jsonp: Jsonp) {}
    
      search (term: string) {
        var search = new URLSearchParams()
        search.set('action', 'opensearch');
        search.set('search', term);
        search.set('format', 'json');
        return this.jsonp
                    .get('http://en.wikipedia.org/w/api.php?callback=JSONP_CALLBACK', { search })
                    .toPromise()
                    .then((response) => response.json()[1]);
      }
    }
    

    We are injecting the Jsonp service to make a GET request against the Wikipedia API with a given search term. Notice that we call toPromise in order to get from an Observable<Response> to a Promise<Response>. Eventually end up with a Promise<Array<string>> as the return type of our search method.

    app.ts

    // check the plnkr for the full list of imports
    import {...} from '...';
    
    @Component({
      selector: 'my-app',
      template: `
        <div>
          <h2>Wikipedia Search</h2>
          <input #term type="text" (keyup)="search(term.value)">
          <ul>
            <li *ngFor="let item of items">{{item}}</li>
          </ul>
        </div>
      `
    })
    export class AppComponent {
      items: Array<string>;
    
      constructor(private wikipediaService: WikipediaService) {}
    
      search(term) {
        this.wikipediaService.search(term)
                             .then(items => this.items = items);
      }
    }
    

    There is not much of a surprise here either. We inject our WikipediaService and expose its functionality via a search method to the template. The template simply binds to keyup and calls search(term.value).

    We unwrap the result of the Promise that the search method of the WikipediaService returns and expose it as a simple array of strings to the template so that we can have *ngFor loop through it and build up a list for us.

    See the example of Promise-based implementation on Plunker


    Where Observables really shine

    Let’s change our code to not hammer the endpoint with every keystroke, but instead only send a request when the user stopped typing for 400 ms

    To unveil such super powers, we first need to get an Observable<string> that carries the search term that the user types in. Instead of manually binding to the keyup event, we can take advantage of Angular’s formControl directive. To use this directive, we first need to import the ReactiveFormsModule into our application module.

    app.ts

    import { NgModule } from '@angular/core';
    import { BrowserModule } from '@angular/platform-browser';
    import { JsonpModule } from '@angular/http';
    import { ReactiveFormsModule } from '@angular/forms';
    
    @NgModule({
      imports: [BrowserModule, JsonpModule, ReactiveFormsModule]
      declarations: [AppComponent],
      bootstrap: [AppComponent]
    })
    export class AppModule {}
    

    Once imported, we can use formControl from within our template and set it to the name “term”.

    <input type="text" [formControl]="term"/>
    

    In our component, we create an instance of FormControl from @angular/form and expose it as a field under the name term on our component.

    Behind the scenes, term automatically exposes an Observable<string> as property valueChanges that we can subscribe to. Now that we have an Observable<string>, overcoming the user input is as easy as calling debounceTime(400) on our Observable. This will return a new Observable<string> that will only emit a new value when there haven’t been coming new values for 400 ms.

    export class App {
      items: Array<string>;
      term = new FormControl();
      constructor(private wikipediaService: WikipediaService) {
        this.term.valueChanges
                  .debounceTime(400)        // wait for 400 ms pause in events
                  .distinctUntilChanged()   // ignore if next search term is same as previous
                  .subscribe(term => this.wikipediaService.search(term).then(items => this.items = items));
      }
    }
    

    It would be a waste of resources to send out another request for a search term that our application already shows the results for. All we have to do to achieve the desired behavior is to call the distinctUntilChanged operator right after we called debounceTime(400)

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W3spoint99
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Asked: January 17, 2025In: Angular

Can’t bind to ‘ngModel’ since it isn’t a known property of ‘input’?

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Can’t bind to ‘ngModel’ since it isn’t a known property of ‘input’? I have this simple input in my component which uses [(ngModel)] : <input type="text" [(ngModel)]="test" placeholder="foo" /> And I get the following error when I launch my app, even if the ...

angularangular formangular template form
  1. Saralyn
    Saralyn Teacher
    Added an answer on January 17, 2025 at 2:02 pm

    For using [(ngModel)] in Angular 2, 4 & 5+, you need to import FormsModule from Angular form... Also, it is in this path under forms in the Angular repository on GitHub: angular / packages / forms / src / directives / ng_model.ts Probably this is not a very pleasurable for the AngularJS developeRead more

    For using [(ngModel)] in Angular 2, 4 & 5+, you need to import FormsModule from Angular form…

    Also, it is in this path under forms in the Angular repository on GitHub:

    angular / packages / forms / src / directives / ng_model.ts

    Probably this is not a very pleasurable for the AngularJS developers as you could use ng-model everywhere anytime before, but as Angular tries to separate modules to use whatever you’d like you to want to use at the time, ngModel is in FormsModule now.

    Also, if you are using ReactiveFormsModule it needs to import it too.

    So simply look for app.module.ts and make sure you have FormsModule imported in…

    import { BrowserModule } from '@angular/platform-browser';
    import { NgModule } from '@angular/core';
    import { FormsModule } from '@angular/forms';  // <<<< import it here
    import { AppComponent } from './app.component';
    
    @NgModule({
      declarations: [
        AppComponent
      ],
      imports: [
        BrowserModule, FormsModule // <<<< And here
      ],
      providers: [],
      bootstrap: [AppComponent]
    })
    
    export class AppModule { }
    

    Also, these are the current starting comments for Angular4 ngModel in FormsModule:

    /**
     * `ngModel` forces an additional change detection run when its inputs change:
     * E.g.:
     * ```
     * <div>{{myModel.valid}}</div>
     * <input [(ngModel)]="myValue" #myModel="ngModel">
     * ```
     * I.e. `ngModel` can export itself on the element and then be used in the template.
     * Normally, this would result in expressions before the `input` that use the exported directive
     * to have and old value as they have been
     * dirty checked before. As this is a very common case for `ngModel`, we added this second change
     * detection run.
     *
     * Notes:
     * - this is just one extra run no matter how many `ngModel` have been changed.
     * - this is a general problem when using `exportAs` for directives!
     */
    

    If you’d like to use your input, not in a form, you can use it with ngModelOptions and make standalone true…

    [ngModelOptions]="{standalone: true}"
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W3spoint99
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W3spoint99Begginer
Asked: December 25, 2024In: Programmers

How to prevent SQL injection in PHP?

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If user input is inserted without modification into an SQL query, then the application becomes vulnerable to SQL injection, like in the following example: $unsafe_variable = $_POST['user_input']; mysql_query("INSERT INTO `table` (`column`) VALUES ('$unsafe_variable')"); That’s because the user can input something ...

mysqlphpsecuritysqlsql-injection
  1. Saralyn
    Saralyn Teacher
    Added an answer on December 25, 2024 at 10:08 am

    The correct way to avoid SQL injection attacks, no matter which database you use, is to separate the data from SQL, so that data stays data and will never be interpreted as commands by the SQL parser. It is possible to create an SQL statement with correctly formatted data parts, but if you don't fulRead more

    The correct way to avoid SQL injection attacks, no matter which database you use, is to separate the data from SQL, so that data stays data and will never be interpreted as commands by the SQL parser. It is possible to create an SQL statement with correctly formatted data parts, but if you don’t fully understand the details, you should always use prepared statements and parameterized queries. These are SQL statements that are sent to and parsed by the database server separately from any parameters. This way it is impossible for an attacker to inject malicious SQL.

    You basically have two options to achieve this:

    1. Using PDO (for any supported database driver):
      $stmt = $pdo->prepare('SELECT * FROM users WHERE name = :name');
      $stmt->execute([ 'name' => $name ]);
      
      foreach ($stmt as $row) {
          // Do something with $row
      }
      
    2. Using MySQLi (for MySQL):
      Since PHP 8.2+ we can make use of execute_query() which prepares, binds parameters, and executes SQL statement in one method:

      $result = $db->execute_query('SELECT * FROM users WHERE name = ?', [$name]);
      while ($row = $result->fetch_assoc()) {
          // Do something with $row
      }
      

      Up to PHP8.1:

      $stmt = $db->prepare('SELECT * FROM employees WHERE name = ?');
      $stmt->bind_param('s', $name); // 's' specifies variable type 'string'
      $stmt->execute();
      $result = $stmt->get_result();
      while ($row = $result->fetch_assoc()) {
          // Do something with $row
      }
      

    If you’re connecting to a database other than MySQL, there is a driver-specific second option that you can refer to (for example, pg_prepare() and pg_execute() for PostgreSQL). PDO is the universal option.


    Correctly setting up the connection

    PDO

    Note that when using PDO to access a MySQL database real prepared statements are not used by default. To fix this you have to disable the emulation of prepared statements. An example of creating a connection using PDO is:

    $dsn = 'mysql:dbname=dbtest;host=127.0.0.1;charset=utf8mb4';
    $dbConnection = new PDO($dsn, 'user', 'password');
    
    $dbConnection->setAttribute(PDO::ATTR_EMULATE_PREPARES, false);
    $dbConnection->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
    

    In the above example, the error mode isn’t strictly necessary, but it is advised to add it. This way PDO will inform you of all MySQL errors by means of throwing the PDOException.

    What is mandatory, however, is the first setAttribute() line, which tells PDO to disable emulated prepared statements and use real prepared statements. This makes sure the statement and the values aren’t parsed by PHP before sending it to the MySQL server (giving a possible attacker no chance to inject malicious SQL).

    Although you can set the charset in the options of the constructor, it’s important to note that ‘older’ versions of PHP (before 5.3.6) silently ignored the charset parameter in the DSN.

    Mysqli

    For mysqli we have to follow the same routine:

    mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT); // error reporting
    $dbConnection = new mysqli('127.0.0.1', 'username', 'password', 'test');
    $dbConnection->set_charset('utf8mb4'); // charset
    

    Explanation

    The SQL statement you pass to prepare is parsed and compiled by the database server. By specifying parameters (either a ? or a named parameter like :name in the example above) you tell the database engine where you want to filter on. Then when you call execute, the prepared statement is combined with the parameter values you specify.

    The important thing here is that the parameter values are combined with the compiled statement, not an SQL string. SQL injection works by tricking the script into including malicious strings when it creates SQL to send to the database. So by sending the actual SQL separately from the parameters, you limit the risk of ending up with something you didn’t intend.

    Any parameters you send when using a prepared statement will just be treated as strings (although the database engine may do some optimization so parameters may end up as numbers too, of course). In the example above, if the $name variable contains 'Sarah'; DELETE FROM employees the result would simply be a search for the string "'Sarah'; DELETE FROM employees", and you will not end up with an empty table.

    Another benefit of using prepared statements is that if you execute the same statement many times in the same session it will only be parsed and compiled once, giving you some speed gains.

    Oh, and since you asked about how to do it for an insert, here’s an example (using PDO):

    $stmt = $db->prepare('INSERT INTO table (column) VALUES (:column)');
    $stmt->execute(['column' => $value]);
    

    Can prepared statements be used for dynamic queries?

    While you can still use prepared statements for the query parameters, the structure of the dynamic query itself cannot be parametrized and certain query features cannot be parametrized.

    For these specific scenarios, the best thing to do is use a whitelist filter that restricts the possible values.

    // Value whitelist
    // $dir can only be 'DESC', otherwise it will be 'ASC'
    if (empty($dir) || $dir !== 'DESC') {
       $dir = 'ASC';
    }
    
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Answer
Saralyn
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SaralynTeacher
Asked: April 27, 2025

Should I learn Java or Kotlin in order to develop Android apps?

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Go Easy with Kotlin, create as many as Class in .kt but if you are having problem with, then also create some class in .java There is no issue if your app has both the classes, ...

AndroidDevelopmentJavaKotlin
  1. Saralyn
    Saralyn Teacher
    Added an answer on April 27, 2025 at 2:01 pm

    Learn Java if: ✅ You want to work on enterprise applications. ✅ You are interested in cloud computing, web services, and microservices. ✅ You prefer a well-established language with strong community support. Learn Kotlin if: ✅ You want to specialize in Android development. ✅ You prefer a modern, conRead more

    Learn Java if:

    ✅ You want to work on enterprise applications.

    ✅ You are interested in cloud computing, web services, and microservices.

    ✅ You prefer a well-established language with strong community support.

    Learn Kotlin if:

    ✅ You want to specialize in Android development.

    ✅ You prefer a modern, concise syntax.

    ✅ You want to explore functional programming & modern backend frameworks.

    Can You Learn Both?

    Yes! Java and Kotlin are interoperable, meaning you can use them together in the same project. Many companies use Java for backend and Kotlin for Android development.

    If you have time, learning both will make you a more versatile developer.

    Final Thoughts

    Both Java and Kotlin have their strengths. In 2025:

    • Java remains strong in enterprise, backend, and cloud applications.
    • Kotlin dominates Android development and is growing in backend applications.

    🚀 Best approach? Start with Java if you’re new, then explore Kotlin to expand your skill set. 🚀

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Saralyn
  • 1
SaralynTeacher
Asked: April 27, 2025

Will AI replace programmers?

  • 1

As a coder, I have some nuanced opinions about AI. I’m an applications developer / designer, and I’ve been coding since I was a teenager. My first system was a Sinclair ZX80! My ...

AIartificial intelligencecodingJavajobprogrammer
  1. Saralyn
    Best Answer
    Saralyn Teacher
    Added an answer on April 27, 2025 at 1:58 pm

    AI is getting smarter, but replacing programmers entirely? That’s not happening anytime soon. What AI Can Do AI can already generate code, debug simple problems, and automate repetitive tasks. Tools like GitHub Copilot and ChatGPT can speed up development by suggesting solutions, writing boilerplateRead more

    AI is getting smarter, but replacing programmers entirely? That’s not happening anytime soon.

    What AI Can Do

    AI can already generate code, debug simple problems, and automate repetitive tasks. Tools like GitHub Copilot and ChatGPT can speed up development by suggesting solutions, writing boilerplate code, and even fixing errors. This means junior-level, repetitive coding tasks are becoming more automated.

    What AI Can’t Do

    Programming isn’t just about writing code—it’s about solving complex problems, understanding user needs, designing scalable systems, and making strategic decisions. AI lacks:

    • Creativity & Critical Thinking – AI can write code, but it doesn’t understand why one approach is better than another.
    • Problem-Solving Skills – Real-world software development isn’t just about syntax; it’s about architecture, security, and optimization.
    • Collaboration & Communication – AI can’t talk to stakeholders, understand business goals, or lead a team.

    The Future of Programming

    Instead of replacing programmers, AI will enhance them. Future programmers will spend less time on repetitive coding and more time on high-level design, debugging, and decision-making. AI will become a powerful assistant, not a replacement.

    Who Should Be Worried?

    • Low-skill, copy-paste coders – If your job is just Googling and pasting Stack Overflow answers, AI might replace you.
    • Routine, repetitive coding jobs – Simple automation tasks are already being taken over by AI.

    Who Will Thrive?

    • Problem-solvers and architects – Those who design, analyze, and optimize systems.
    • Developers who adapt to AI tools – The best programmers will use AI to be 10x more productive.

    Bottom Line

    AI won’t replace programmers—it will replace bad programmers. The best developers will learn to work alongside AI, using it as a tool to build even better software.

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W3spoint99
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Asked: January 17, 2025In: Reactjs

How to programmatically navigate using React Router?

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How to programmatically navigate using React Router? With react-router I can use the Link element to create links which are natively handled by react router. I see internally it calls this.context.transitionTo(...). I want to do a navigation. Not from a link, but from a dropdown selection (as an ...

javascriptreact routerreactjs
  1. Saralyn
    Saralyn Teacher
    Added an answer on January 17, 2025 at 2:00 pm

    The useHistory() hook is now deprecated. If you are using React Router 6, the proper way to navigate programmatically is as follows: import { useNavigate } from "react-router-dom"; function HomeButton() { const navigate = useNavigate(); function handleClick() { navigate("/home"); } return ( <buttRead more

    The useHistory() hook is now deprecated. If you are using React Router 6, the proper way to navigate programmatically is as follows:

    import { useNavigate } from "react-router-dom";
    
    function HomeButton() {
      const navigate = useNavigate();
    
      function handleClick() {
        navigate("/home");
      }
    
      return (
        <button type="button" onClick={handleClick}>
          Go home
        </button>
      );
    }
    
    

    React Router v5.1.0 with hooks

    There is a new useHistory hook in React Router >5.1.0 if you are using React >16.8.0 and functional components.

    import { useHistory } from "react-router-dom";
    
    function HomeButton() {
      const history = useHistory();
    
      function handleClick() {
        history.push("/home");
      }
    
      return (
        <button type="button" onClick={handleClick}>
          Go home
        </button>
      );
    }
    

    React Router v4

    With v4 of React Router, there are three approaches that you can take to programmatic routing within components.

    1. Use the withRouter higher-order component.
    2. Use composition and render a <Route>
    3. Use the context.

    React Router is mostly a wrapper around the history library. history handles interaction with the browser’s window.history for you with its browser and hash histories. It also provides a memory history which is useful for environments that don’t have a global history. This is particularly useful in mobile app development (react-native) and unit testing with Node.

    A history instance has two methods for navigating: push and replace. If you think of the history as an array of visited locations, push will add a new location to the array and replace will replace the current location in the array with the new one. Typically you will want to use the push method when you are navigating.

    In earlier versions of React Router, you had to create your own history instance, but in v4 the <BrowserRouter>, <HashRouter>, and <MemoryRouter> components will create a browser, hash, and memory instances for you. React Router makes the properties and methods of the history instance associated with your router available through the context, under the router object.

    1. Use the withRouter higher-order component

    The withRouter higher-order component will inject the history object as a prop of the component. This allows you to access the push and replace methods without having to deal with the context.

    import { withRouter } from 'react-router-dom'
    // this also works with react-router-native
    
    const Button = withRouter(({ history }) => (
      <button
        type='button'
        onClick={() => { history.push('/new-location') }}
      >
        Click Me!
      </button>
    ))
    

    2. Use composition and render a <Route>

    The <Route> component isn’t just for matching locations. You can render a pathless route and it will always match the current location. The <Route> component passes the same props as withRouter, so you will be able to access the history methods through the history prop.

    import { Route } from 'react-router-dom'
    
    const Button = () => (
      <Route render={({ history}) => (
        <button
          type='button'
          onClick={() => { history.push('/new-location') }}
        >
          Click Me!
        </button>
      )} />
    )
    

    3. Use the context*

    But you probably should not

    The last option is one that you should only use if you feel comfortable working with React’s context model (React’s Context API is stable as of v16).

    const Button = (props, context) => (
      <button
        type='button'
        onClick={() => {
          // context.history.push === history.push
          context.history.push('/new-location')
        }}
      >
        Click Me!
      </button>
    )
    
    // you need to specify the context type so that it
    // is available within the component
    Button.contextTypes = {
      history: React.PropTypes.shape({
        push: React.PropTypes.func.isRequired
      })
    }
    

    1 and 2 are the simplest choices to implement, so for most use cases, they are your best bets.

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W3spoint99
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W3spoint99Begginer
Asked: January 17, 2025In: Reactjs

Error message "error:0308010C:digital envelope routines::unsupported"

  • 0

Error message “error:0308010C:digital envelope routines::unsupported”.  Created the default IntelliJ IDEA React project and got this: Error: error:0308010C:digital envelope routines::unsupported at new Hash (node:internal/crypto/hash:67:19) at Object.createHash (node:crypto:130:10) at module.exports (/Users/user/Programming Documents/WebServer/untitled/node_modules/webpack/lib/util/createHash.js:135:53) ...

node.jsreactjswebpack
  1. Saralyn
    Saralyn Teacher
    Added an answer on January 17, 2025 at 1:59 pm

    The error comes from your dependency relying on an obsolete version of SSL, so you have two good, and two questionable-at-best options: 1. Try to just reinstall your dependency Delete your node_modules folder and rerun npm install. If your dependency relies on compiling against whatever version of NRead more

    The error comes from your dependency relying on an obsolete version of SSL, so you have two good, and two questionable-at-best options:

    1. Try to just reinstall your dependency

    • Delete your node_modules folder and rerun npm install. If your dependency relies on compiling against whatever version of Node you have installed, this may immediately fix the problem. This is the least likely solution to work, but may fix the problem without any “real” work on your part so is always worth trying.

    2. Update your dependency

    • Almost all dependencies with this problem have a newer version available that you can install instead. Find out which version of your dependency corresponds to after Node 18 became the LTS version of Node, band uplift your dependency to that version.

    This is, really, the only proper solution: update your dependencies, because just like Node.js itself, they can leave your project vulnerable to attacks and exploits.

    3. Downgrade to Node.js v16.

    • You can downgrade Node itself so that you’re using a version that uses the old, insecure, version of LibSSL. That doesn’t “solve” the problem of running insecure and potentially exploitable code, of course, but your code will at least run.

    (You can either do that using the official Node installers, or you can use something like nvm. For Windows, use nvm-windows.)

    This is, obviously, a bad idea. As is the next one:

    4. Tell Node to use the legacy OpenSSL provider

    On Unix-like (Linux, macOS, Git bash, etc.):

    export NODE_OPTIONS=--openssl-legacy-provider
    

    On Windows command prompt:

    set NODE_OPTIONS=--openssl-legacy-provider
    

    On PowerShell:

    $env:NODE_OPTIONS = "--openssl-legacy-provider"
    

    When Node 18 had just become the active LTS options 1 and 2 weren’t really available, but for anyone still finding this answer, 3 and 4 should no longer be considered serious options in any way.

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